#include<bits/stdc++.h>
using namespace std;
int main(){
int n,i,j,s=0;
char a;
cin>>n>>a;
int m=int(sqrt(double(n+1)/2));//算行数的公式,减少循环
int f=2*m-1;
for( i=0;i<m;i++){
for( j=0;j<i;j++)cout<<" ";
for(j=0;j<f-2*i;j++){cout<<a;s++;}
cout<<endl;
}
for(i=m-2;i>=0;i--){
for(j=0;j<i;j++)cout<<" ";
for(j=0;j<f-2*i;j++){cout<<a;s++;}
cout<<endl;
}
cout<<n-s;
}