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2.6.2π的计算

发布时间 2023-11-01 11:24:53作者: Haaan

π的计算

import random
S = 1e6
N = 0
for i in range(int(S)):
    x = random.random()
    y = random.random()
    d = (x-0.5)**2+(y-0.5)**2
    if d<=0.5**2:
        N+=1
    else:
        pass
PI = 4*N/S
print(PI)
print("3110")