实验1

 1 #include <stdio.h>
 2 int main ()
 3 {
 4     printf(" o \n");
 5     printf("<H>\n");
 6     printf("I I \n");
 7     
 8     return 0;
 9     
10  } 

 1 #include <stdio.h>
 2 int main ()
 3 {
 4     float a , b , c;
 5     scanf ("%f%f%f" , &a ,&b ,&c);
 6     
 7     if (a + b >c && a- b > c)
 8     printf ("能构成三角形\n");
 9      else
10      
11      printf("不能构成三角形\n");
12       
13     
14     return 0;
15     
16  } 

 1 #include <stdio.h>
 2 int main ()
 3 {
 4     char ans1 , ans2;
 5     
 6     printf("每次课前认真预习、课后及时复习了没？（输入y或Y表示有， 输入n或N表示没有）；"); 
 7     ans1 = getchar();
 8     
 9     getchar();
10     
11     printf("\n动手敲代码实践了没？（输入y或Y表示有， 输入n或N表示没有）；");
12     ans2 = getchar();
13     
14     getchar();
15     
16     if(ans1 == 'y'||ans1 == 'Y'&&(ans2 == 'y' || ans2 == 'Y'))
17     printf ("\n罗马不是一天建成的，继续保持哦:)\n");
18     
19     else
20     printf("\n罗马不是一天毁灭的，我们来建设吧\n");
21     
22     
23     return 0;
24     
25  } 

 1 #include <stdio.h>
 2 int main ()
 3 {
 4     double x, y;
 5     char c1 , c2 , c3;
 6     int a1 , a2 , a3;
 7     
 8     scanf("%d%d%d", &a1 , &a2 ,&a3);
 9     printf("a1 =%d ,a2 = %d , a3 = %d\n", a1 ,a2 , a3);
10     
11     scanf("%c%c%c", &c1 , &c2 , &c3);
12     printf("c1 = %c , c2 = %c , c3 = %c\n",c1 , c2 ,c3 );
13     
14     scanf ("%lf%lf",&x , &y );
15     printf ("x = %lf , y = %lf\n" ,x,y);
16         
17     
18     return 0;
19     
20  } 

 1 #include<stdio.h>
 2 int main(){
 3     int year;
 4     int j = 1;
 5     double i = 1;
 6     int t,m;
 7     
 8     while(j<=9){
 9         i*=10;
10         j++;
11         
12     }
13     year = i/(60*60*24*365);
14 
15     t = i/(60*60*24*365)*100;
16     m = t%100;
17     if(m>=50)
18     year+=1;
19     else if(m<50)
20     year = year+0;
21     
22     
23     printf("10亿秒约等于%d年\n",year);
24     
25     
26     
27 
28 
29 
30 
31 return 0;
32 }

 1 #include<stdio.h>
 2 #include<math.h>
 3 int main()
 4 {
 5     double x , ans;
 6     
 7     scanf("%lf", &x);
 8     ans = pow(x,365);
 9     printf("%.2lf的365次方: %.2f\n", x , ans);
10          
11      
12     
13 
14     
15     
16 
17 
18 
19 
20 return 0;
21 }

#include<stdio.h>
#include<math.h>
int main()
{
double x , ans;

while(scanf("%lf",&x)!=EOF)
{
ans = pow(x,365);
printf("%.2f的365次方为：%.2f\n",x,ans);
printf("\n");}

 

 

return 0;
}

 1 #include<stdio.h>
 2 int main(){
 3     double c,f;
 4     
 5     while(scanf("%lf",&c)!=EOF)
 6     {
 7         f = 9*c/5 + 32;
 8         printf("摄氏度c = %.2f时，华氏度f = %.2f\n",c,f); 
 9         printf("\n");
10     }
11 
12 return 0;
13 }

 1 #include<stdio.h>
 2 #include<math.h>
 3 int main(){
 4     int a,b,c;
 5     double s,area;
 6     while(scanf("%d%d%d",&a,&b,&c)!=EOF)
 7     {
 8         s = (a+b+c)/2;
 9         area = sqrt(s*(s-a)*(s-b)*(s-c));
10         printf("a = %d,b = %d,c = %d,area = %.3f\n",a,b,c,area);
11         printf("\n");
12     }
13 
14 return 0;
15 }