class Solution {
public:
int maxSubArray(vector<int>& nums) {
int n=nums.size(),res=-0x3f3f3f3f;
for (int i = 0; i < n;)//枚举以i为起点的区间
{
int j=i,sum=0;
while(j<n)
{
sum+=nums[j];
res=max(res,sum);
if(sum<=0) break;
j++;
}
i=j+1;
}
return res;
}
};
连续子数组的最大和
发布时间 2023-04-19 16:58:52作者: 穿过雾的阴霾