T1:Similar String
模拟
代码实现
#include <bits/stdc++.h>
#define rep(i, n) for (int i = 0; i < (n); ++i)
using namespace std;
char nomalize(char a) {
if (a == '1') return 'l';
if (a == '0') return 'o';
return a;
}
string nomalize(string s) {
rep(i, s.size()) s[i] = nomalize(s[i]);
return s;
}
int main() {
int n;
cin >> n;
string s, t;
cin >> s >> t;
s = nomalize(s);
t = nomalize(t);
if (s == t) puts("Yes");
else puts("No");
return 0;
}