#include<bits/stdc++.h>
using namespace std;
double fact (int a)//计算n的阶乘
{ double t=1.0;
int i;
for(i=1;i<=a;i++)
t=t*i;
return t;
}
double mi (int b, double angle)//计算x的n次方
{
int j=1;
double x=angle;
for(j=1;j<b;j++)
x=x*angle;
return x;
}
int main()
{
int x,i=1,m=1,e=1;
const double pi=3.141593;
double p1,p2,sum=1.0,k=1,angle,shang=1;
double fact (int);
double mi (int b,double angle);//
cout<<"请输入一个角度值 ";
cin>>x;
angle=pi*x/180;
while(fabs(k)>=1e-7)//10的n次方的表达
{
e=-e;//挺妙
m=2*i;
p1=fact(m)*e;
p2=mi(m,angle);
k=p2/p1;
shang=k;
sum=sum+k;
i++;
}
cout<<"cos("<<x<<")"<<'='<<sum<<endl;
system("pause");
}
这道题明显用函数比较方便