省选一轮模板复习

发布时间 2023-03-31 16:35:16作者: SF71-H

一、堆

#include <bits/stdc++.h>
using namespace std;
int n;
priority_queue < int, vector < int >, greater < int > > heap;
signed main () {
	scanf ("%d", &n);
	while (n --) {
		int op;
		scanf ("%d", &op);
		if (op == 1) {
			int x;
			scanf ("%d", &x);
			heap.push (x);
		}
		else if (op == 2) {
			printf ("%d\n", heap.top ());
		}
		else {
			heap.pop ();
		}
	}	
	return 0;
}

二、负环

#include <bits/stdc++.h>
using namespace std;
#define int long long
int T, n, m, cnt, head[2005], in[2005], vis[2005], dis[2005];
struct edge {
	int to, nxt, val;
} ed[6005];
inline void add_edge (int u, int v, int w) {
	cnt ++;
	ed[cnt].to = v;
	ed[cnt].val = w;
	ed[cnt].nxt = head[u];
	head[u] = cnt;
}
inline bool SPFA (int s) {
	for (int i = 1;i <= n; ++ i) in[i] = vis[i] = 0, dis[i] = 1e18;
	queue < int > q;
	q.push (s); vis[s] = 1; dis[s] = 0; in[s] ++;
	if (in[s] > n) return true;
	while (!q.empty ()) {
		int u = q.front ();
		q.pop (); vis[u] = 0;
		for (int i = head[u]; i ; i = ed[i].nxt) {
			int v = ed[i].to;
			int w = ed[i].val;
			if (dis[v] > dis[u] + w) {
				dis[v] = dis[u] + w;
				if (!vis[v]) {
					vis[v] = 1;
					in[v] ++;
					q.push (v);
					if (in[v] > n) return true;
				}
			}
		}
	}
	return false;
}
signed main () {
	scanf ("%lld", &T);
	while (T --) {
		scanf ("%lld %lld", &n, &m);
		cnt = 0;
		for (int i = 1;i <= n; ++ i) head[i] = 0;
		for (int i = 1;i <= m; ++ i) {
			int u, v, w;
			scanf ("%lld %lld %lld", &u, &v, &w);
			if (w >= 0) {
				add_edge (u, v, w);
				add_edge (v, u, w);
			}
			else {
				add_edge (u, v, w);
			}
		}
		if (SPFA (1)) printf ("YES\n");
		else printf ("NO\n");
	}
	return 0;
}

三、ST 表

#include <bits/stdc++.h>
using namespace std;
inline int read () {
	int x = 0, f = 0;
	char c = getchar ();
	for ( ; c < '0' || c > '9' ; c = getchar ()) f |= (c == '-');
	for ( ; c >= '0' && c <= '9' ; c = getchar ()) x = (x << 1) + (x << 3) + (c ^ 48);
	return x; 
}
int n, m, a[100005], lg[100005], st[100005][22];
inline int query (int l, int r) {
	int k = lg[r - l + 1];
	return max (st[l][k], st[r - (1 << k) + 1][k]);
}
signed main () {
	n = read (); m = read ();
	for (int i = 1;i <= n; ++ i) a[i] = read ();
	lg[0] = -1;
	for (int i = 1;i <= n; ++ i) lg[i] = lg[i >> 1] + 1;
	for (int i = 1;i <= n; ++ i) st[i][0] = a[i];
	for (int j = 1;j <= 21; ++ j) {
		for (int i = 1;i + (1 << j) - 1 <= n; ++ i) {
			st[i][j] = max (st[i][j - 1], st[i + (1 << (j - 1))][j - 1]);
		}
	}
	while (m --) {
		int l, r;
		l = read (); r = read ();
		printf ("%d\n", query (l, r));
	}
	return 0;
}