实验三

发布时间 2023-03-30 17:39:19作者: 郑之行

任务1

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <windows.h>
#define N 80

void print_text(int line, int col, char text[]);
void print_spaces(int n); 
void print_blank_lines(int n); 

int main() 
{
    int line, col, i;
    char text[N] = "hi, April~";
    srand(time(0));
    for(i = 1; i <= 10; ++i) 
    {
        line = rand() % 25;
        col = rand() % 80;
        print_text(line, col, text);
        Sleep(1000);
    } 
return 0;
}

void print_spaces(int n) 
{
    int i;
    for(i = 1; i <= n; ++i)
    printf(" ");
}

void print_blank_lines(int n) 
{
    int i;
    for(i = 1; i <= n; ++i)
    printf("\n");
}

void print_text(int line, int col, char text[]) 
{
    print_blank_lines(line-1); 
    print_spaces(col-1); 
    printf("%s", text); 
}

输出10次间隔1~24行、1~79空格的“hi,April~”

 

任务2

#include <stdio.h>
long long fac(int n); 

int main() 
{
    int i, n;
    printf("Enter n: ");
    scanf("%d", &n);
    for (i = 1; i <= n; ++i)
    printf("%d! = %lld\n", i, fac(i));
    return 0;
} 

long long fac(int n) 
{
    static long long p = 1;
    printf("p = %lld\n", p);
    p = p * n;
    return p;
}

#include <stdio.h>

int func(int, int); 

int main() 
{
    int k = 4, m = 1, p1, p2;
    p1 = func(k, m); 
    p2 = func(k, m); 
    printf("%d, %d\n", p1, p2);
    return 0;
}

int func(int a, int b)
{
    static int m = 0, i = 2;
    i += m + 1;
    m = i + a + b;
    return m;
}

static首次调用之后变量存在,但不能被其他函数使用。再次回到函数中时使用上次结果。

任务3

 

#include <stdio.h>

long long func(int n);

int main() 
{
    int n;
    long long f;
    while (scanf("%d", &n) != EOF) 
    {
        f = func(n);
        printf("n = %d, f = %lld\n", n, f);
    } 
    return 0;
}

long long func(int n)
{
    int f;
    if(n>1)
        f=2*func(n-1)+1;
    else
        f=1;
    n=n-1;
    return f;
} 

任务4

#include <stdio.h>

int func(int n, int m);

int main() 
{
    int n, m;
    while(scanf("%d%d", &n, &m) != EOF)
    printf("n = %d, m = %d, ans = %d\n", n, m, func(n, m));
    return 0;
}

int func(int n,int m)
{
    int a=1,b=1,i,f;
    func(0,0)=1;
    f=func(n-1,m)+func(n-1,m-1);
    n=n-1;
    m=m-1;
    return f;
}