import itertools # 列表嵌套的拆解
a = [ [(1,2),(2,3),(5,6)], [(22,33),(12,78)] ]
new_a = list( itertools.chain.from_iterable(a) )
## 结果：
[(1, 2), (2, 3), (5, 6), (22, 33), (12, 78)]嵌套列表拆解
发布时间 2023-03-23 14:40:23作者: 云飞01
import itertools # 列表嵌套的拆解
a = [ [(1,2),(2,3),(5,6)], [(22,33),(12,78)] ]
new_a = list( itertools.chain.from_iterable(a) )
## 结果：
[(1, 2), (2, 3), (5, 6), (22, 33), (12, 78)]