android权限申请

权限申请

1. android 6.0之前申请权限：以PHONE_CALL 为例

manifest添加如下内容：
<uses-permission android:name="android.permission.CALL_PHONE" />

public class PTest extends AppCompatActivity {
 @Override
 protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_ptest);
 }
​
 public void makeCall(View view) {
    Intent intent = new Intent(Intent.ACTION_CALL);
    intent.setData(Uri.parse("tel:10086"));
    startActivity(intent);
 }
}

2. android 6.0之后

使用如上方法申请权限，报错信息如下，权限未申请成功

正确方法：

manifest添加如下内容：
<uses-permission android:name="android.permission.CALL_PHONE" />

public class PTest extends AppCompatActivity {
​
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_ptest);
    }
​
    public void makeCall(View view) {
        //未申请权限-->调用ActivityCompat.requestPermissions申请权限
       if (ContextCompat.checkSelfPermission(PTest.this,           Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
            ActivityCompat.requestPermissions(PTest.this, new String[]{Manifest.permission.CALL_PHONE}, 1);
        }else {
            call();
        }
    }
      void call(){
        //call
        Intent intent = new Intent(Intent.ACTION_CALL);
        intent.setData(Uri.parse("tel:10086"));
        startActivity(intent);
    }
    //权限申请执行结果
    @Override
    public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
        super.onRequestPermissionsResult(requestCode, permissions, grantResults);
        switch (requestCode) {
            case 1:
                if (grantResults.length > 0 && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
                    call();
                }else {
                    Toast.makeText(this,"you denied the permission", Toast.LENGTH_SHORT).show();
                }
                break;
            default:
        }
    }
}