ones twos and

Replacing gcc and g++ with GNU version in macOS

After we install Xcode Command Line Tools, we will get gcc and g++ in /Library/Developer/CommandLineTools/usr/bin and the same contents in /usr/bin. B ......
Replacing version macOS with GNU

CF1858D Trees and Segments

原题 翻译 这题预期说是\(dp\),不如说是预处理吧233 首先我们同时考虑两维限制是很困难的,如果我们想直接\(dp\)要设很多状态,复杂度爆炸 因此我们考虑暴力枚举一维。具体的,我们枚举把\([l,r]\)内的所有数染成\(0\),我们可以通过前缀和得到操作次数\(t\)(即为区间内\(1\) ......
Segments 1858D Trees 1858 and

How to fix Fetch TypeError in Node.js All In One

How to fix Fetch TypeError in Node.js All In One TypeError: terminated at Fetch.onAborted (node:internal/deps/undici/undici:11000:53) ......
TypeError Fetch Node How All

Fox and Minimal path 题解

Fox and Minimal path 题目大意 构造一张无向图,使得从 \(1\) 到 \(2\) 的最短路数量为 \(k\)。 思路分析 我们首先可以发现当 \(k = 2^t\) 时的构造方式: 其中只有 \(O(\log k)\) 个点。 当 \(k\not = 2^t\) 时,我们可以将 ......
题解 Minimal path Fox and

How to fix macOS Finder not support semicolon symbol in filename error All In One

How to fix macOS Finder not support semicolon symbol in filename error All In One macOS Finder 不支持文件名中包含 : 分号 bug ❌ ......
semicolon filename support Finder symbol

ES2023 Array new features All In One

ES2023 Array new features All In One change Array by copy ......
features Array 2023 All new

How to use Node.js rename files in folder All In One

How to use Node.js rename files in folder All In One fs.rename fs.renameSync fsPromises.rename ......
folder rename files Node How

How to parse OR AND within text

假设你有一行 String condition = "A or B and C"; 语句,请问怎么做才能变成一行真正的逻辑表达式(能在计算机中运行计算)? Resolution 声明一个List<List<String>>结构; 先分割 or ; 变成 [ A, B and C ] 不包含and的, ......
within parse text How AND

doris建表报错 errCode = 2, detailMessage = Scale of decimal must between 0 and 9. Scale was set to: 10

doris建表报错 问题背景 当我从Mpp库向doris库中导数据时,需要先创建对应的数据表,将Mpp库中表的建表语句略作修改后,在doris服务器上运行 CREATE TABLE opt_connect_box_v8 ( CNT_BOX_ID char(72) NOT NULL, CNT_BOX_ ......
表报 Scale detailMessage decimal between

Node.js multi threads All In One

Node.js multi threads All In One Node.js 多线程 worker_threads Worker threads 工作线程 child_process 子进程 Cluster 集群 ......
threads multi Node All One

Cisco Nexus 9000 系列交换机系统软件 NX-OS Standalone 10.4(1)F and ACI Mode 16.0(3e) 发布

Cisco Nexus 9000 系列交换机系统软件 NX-OS Standalone 10.4(1)F and ACI Mode 16.0(3e) 发布 Cisco Nexus 9000 Series Switches, NX-OS Standalone 10.4(1)F and ACI Mode ......
交换机 Standalone 系统 Cisco Nexus

How to delete a file in Node.js All In One

How to delete a file in Node.js All In One fs.unlink fsPromises.unlink fs.unlinkSync ......
delete Node file How All

How to fix Tailwind CSS colors not work in Next.js All In One

How to fix Tailwind CSS colors not work in Next.js All In One Tailwind CSS & Next.js 13 ......
Tailwind colors Next work How

[AGC032F] One Third

非常好题目。 在一个大小为 \(1\) 的圆上选出 \(n\) 条半径将其分为 \(n\) 块,记每块的面积为 \(S_1,S_2,\dots,S_n\),求 \[\min_{i=1}^{n}\{|S_i-\frac{1}{3}|\} \]的期望值。答案对 \(10^9+7\) 取模。 \(2\le ......
Third 032F AGC 032 One

F. Mahmoud and Ehab and yet another xor task 线性基

Problem - F - Codeforces 题意:给出一个长度为n的数组,然后给出q次询问。 对于每次询问,给出一个l和一个x,请你求出在[1,l]这个区间内,有多少个子序列是好的,好的的定义是这个子序列的异或和为x。 做法:考虑线性基,先离线处理询问,对其l排序。然后对于l,求该情况下的线性 ......
线性 and Mahmoud another Ehab

哈希表 知识速记(9/11 and 9/13)

哈希表 拉链法 #include <cstring> #include<string> #include <iostream> using namespace std; const int N = 100003; int h[N], e[N], ne[N], idx; void insert(int ......
知识 and 11 13

Node.js child_process spawn All In One

Node.js child_process spawn All In One Node.js 多线程 How to run Python script code in Node.js? 如何在 Node.js 中运行 Python 脚本代码? sys.stdout.flush() ......
child_process process child spawn Node

error Mixed spaces and tabs no-mixed-spaces-and-tabs

运行Vue项目出现下面截图中的这个问题 百度翻译一下,说是不能同时使用tab键和空格来对代码进行缩进。看了一下代码,确实有行代码缩进了6个字符,改回来正常运行。 ......

Python list replication All In One

Python list replication All In One ......
replication Python list All One

abc226E - Just one

E - Just one 怎么感觉大家都这么懂啊。 结论就是基环森林才有解 证明的话大概是这样 首先不是同一个连通块的话则互不相干,分开讨论即可。 如果一个点的度为1,那么它的出边唯一确定,那么我们可以删去这些点,删去的同时会造成一些新的点度为1,不断扩展即可,同时注意判断无解情况,有点类似于拓扑排 ......
226E Just abc 226 one

Transformer-empowered Multi-scale Contextual Matching and Aggregation for

Transformer-empowered Multi-scale Contextual Matching and Aggregation for Multi-contrast MRI Super-resolution(阅读文献)10.12 基于变压器的磁共振多对比度超分辨率多尺度背景匹配与聚合 摘 ......

2023.9.13 greedy and DS

CF1439C 考虑修改操作,由于序列是单调的,所以只需要线段树二分出修改的区间即可。 考虑查询,一定是若干个连续段,设一开始是 \(y\),这个连续段结束后,\(y\) 至少减去一半,所以连续段个数是 \(\log\) 级别。 在线段树上遍历即可。 ......
greedy 2023 and 13 DS

frequently used character, numeric, and date functions

# Character functions ## ANYALNUM(str, startpos) Return position of first occurrence of any alphabetic or numeric value after or at the start postion ......
frequently character functions numeric date

Fetch API res.buffer vs res.arrayBuffer All In One

Fetch API res.buffer vs res.arrayBuffer All In One ......
arrayBuffer res buffer Fetch API

How to fix Node.js fs.readFileSync toString Error All In One

How to fix Node.js fs.readFileSync toString Error All In One ......
readFileSync toString Error Node How

SQLAlchemy: What's the difference between flush() and commit()?

SQLAlchemy: What's the difference between flush() and commit()? https://pyquestions.com/sqlalchemy-what-s-the-difference-between-flush-and-commit A Se ......
SQLAlchemy difference between commit flush

产品 NPS All In One

产品 NPS All In One NPS / Net Promoter Score / 净推荐值 什么是净推荐值 净推荐值(NPS)又称净促进者得分,是一种计量某个客户将会向其他人推荐某个企业或服务可能性的指数。 它是最流行的顾客忠诚度分析指标,专注于顾客口碑如何影响企业成长。通过密切跟踪净推荐值... ......
产品 NPS All One In

Failed to connect to server: hadoop/ip:9000: try once and fail.

hadoop 连接失败,报如下错误! java.net.ConnectException: Connection refused at sun.nio.ch.SocketChannelImpl.checkConnect(Native Method) at sun.nio.ch.SocketChann ......
connect Failed server hadoop 9000

Concurrency and Parallelism

简而言之,Concurrency(并发)就是交替执行多个任务,而 Parallelism(并行)是同时执行多个任务。 Concurrency Parallelism 多线程和硬件 在单核CPU中,只有并发,没有并行; 编程中,编程语言调用系统的接口,编程语言只负责调用,至于是并发还是并行,还得取决于 ......
Concurrency Parallelism and

CF1867A green_gold_dog, array and permutation

思路 很简单的一道题,洛谷大概都不会开放题解通道?(实际上貌似每场比赛的 A 都没开放?) 显然,对于原数组较小的数,我们尽量让大的数,取全排列的较小的数,这样可以保证差是逐渐变小的,也就让 \(c\) 数组差异变大。 所以直接拿个 struct 存,然后两边排序就好。 AC code #inclu ......
green_gold_dog permutation 1867A green array